First, let's calculate the cross-section of the pipeline. The radius of the tube is half the diameter:
[tex]r= \frac{0.250 m}{2}=0.125 m [/tex]
And the cross-sectional area is:
[tex]A= \pi r^2 = \pi (0.125 m)^2 =0.049 m^2[/tex]
The volumetric flow rate is [tex]\rho = 1.55m^3 /s[/tex]. If we divide this value by the cross-sectional area of the pipeline, we get the flow speed of the gas:
[tex]v= \frac{\rho}{A}= \frac{1.55 m^3}{0.049 m^2}=31.6 m/s [/tex]
