1. n/2-1/3-1=1/6
n/2=1/6+1/3+1
n/2=1/6+2/6+6/6
n/2=9/6=3/2
n=3/2*2=3
check: abs(3/2-1/3)-1=1/6, abs(9/6-2/6)-1= 1/6, 7/6-1=1/6, 1/6 =1/6
3 is a root
2. -(n/2-1/3)-1=1/6
-n/2+1/3-1=1/6
-n/2-2/3=1/6
-n/2=1/6+2/3
-n/2=1/6+4/6
-n/2=5/6
n=-2*5/6=-5/3=-1 2/3
check : abs((-5/3)/2-1/3) -1=1/6
abs(-5/6-1/3) -1 =1/6, abs(-5/6-2/6) -1=1/6, abs (-7/6)-1=1/6, 7/6-1=1/6, 1/6=1/6
so -5/3 or -1 2/3 is also root
so two roots 3 and -5/3(that can be written as -1 2/3)
