Respuesta :

Ivka93
The perimeter of one spiral: D*π, D=12a+6b⇒
                                                              (12a+6b)*π=6*π(2a+b)=18.85(2a+b)

A telephone chord has 8 circular spirals so total length of chord is:
8*18.85(2a+b)=146(2a+b)=292a+146b
The total length of telephone chord is 292a+146b.


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