Respuesta :

sadiyahaaqilah
the zeros are x= 0,-5,-8. the zeros are the x values where the graph intersects the x-axis. to find the zeros, you have to replace y with zero then solve for x.
YourHelperAdi

Given Expression

[tex] \rm \hookrightarrow \: x ( \: x^2+13x+40)[/tex]

Can Be Written As

[tex] \rm \hookrightarrow \: {x}^{2} + 13x + 40[/tex]

Now,

[tex] \rm \hookrightarrow \: {x}^{2} + 5x + 8x+ 40[/tex]

[tex] \rm \hookrightarrow \: {x}(x +5) + 8(8x + 5)[/tex]

[tex] \star\boxed{ \rm { \pmb {\pmb {\pmb\pink\hookrightarrow \pink{ \:( x + 5)(x + 8)}}}}}[/tex]

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