Respuesta :

naǫ
[tex]25x^2+5x-12=0 \\ 25x^2-15x+20x-12=0 \\ 5x(5x-3)+4(5x-3)=0 \\ (5x+4)(5x-3)=0 \\ 5x+4=0 \ \lor \ 5x-3=0 \\ 5x=-4 \ \lor \ 5x=3 \\ x=-\frac{4}{5} \ \lor \ x=\frac{3}{5} \\ \boxed{x=-\frac{4}{5} \hbox{ or } x=\frac{3}{5}}[/tex]
solve your equation step-by-step.

25x2+5x−12=0

Factor left side of equation.

(5x−3)(5x+4)=0

Set factors equal to 0.

5x−3=0 or 5x+4=0

x=3/5 or x=−4/5

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