(The average of five consecutive integers starting from m) - (The average of six consecutive integers starting from m) is?

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02-08-2017
Mathematics

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(The average of five consecutive integers starting from m) - (The average of six consecutive integers starting from m) is?

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irspow irspow · Answer 1 · 2017-08-02T18:08:55+02:00

irspow irspow

02-08-2017

So five consecutive integers starting from m are m, m+1...m+4

So the average of these terms is:

(5m+10)/5

And the average of six of these terms is:

(6m+15)/6

So the difference of these averages is:

d=(5m+10)/5-(6m+15)/6

d=(6(5m+10)-5(6m+15))/30

d=(30m+60-30m-75)/30

d=-15/30

d=-1/2

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