Answer:
The area of rhombus ABCD is 11 cm².
Step-by-step explanation:
Given information: ABCD is a rhombus AC = 5.5 cm and BD = 4 cm.
AC and BD are two diagonals of rhombus.
The area of a rhombus is
[tex]A=\frac{1}{2}\times d_1\times d_2[/tex]
[tex]A=\frac{1}{2}\times AC\times BD[/tex]
[tex]A=\frac{1}{2}\times 5.5\times 4[/tex]
[tex]A=11[/tex]
Therefore the area of rhombus ABCD is 11 cm².
