as far as I can tell
[tex]\bf y=(6x+1)^5(x^4-5)^6\implies ln(y)=ln[\ (6x+1)^5(x^4-5)^6\ ]
\\\\\\
ln(y)=ln[(6x+1)^5]+ln[(x^4-5)^6]
\\\\\\
ln(y)=5ln[(6x+1)]+6ln[(x^4-5)]
\\\\\\
\cfrac{\frac{dy}{dx}}{y}=5\cdot \cfrac{6}{6x+1}+6\cdot \cfrac{4x^3}{x^4-5}
\\\\\\
\cfrac{\frac{dy}{dx}}{y}=\cfrac{30}{6x+1}+\cfrac{24x^3}{x^4-5}
\\\\\\
\cfrac{dy}{dx}=y\left[ \cfrac{30}{6x+1}+\cfrac{24x^3}{x^4-5} \right][/tex]
