[tex]\bf \textit{area of a rectangle}=A=length\times width\implies \cfrac{A}{width}=length
\\\\\\
thus\quad
\begin{cases}
A=x^3+x^2-7x+2\\
width=x-2
\end{cases}\implies \cfrac{x^3+x^2-7x+2}{x-2}=length[/tex]
hint: divisor is x-2 form, thus you can use syntheric division
