I'm going to use "x" because the program lets me put in exponents.
4[tex] x^{2} [/tex]-6x+2+3[tex] x^{2} [/tex]-1
7[tex] x^{2} [/tex]-6a-1
Then factor
(7x+1)(x-1)
Set each to 0 to solve for x
x-1=0 is x=1
7x+1=0
7x=-1
x=[tex] \frac{-1}{7} [/tex]
So your answers are x=1 and x=[tex] \frac{-1}{7} [/tex]
