[tex]-2[/tex]
1) In this problem, we need to make use of the order of operations.
2) Notice that we have divisions, so let's prioritize the division inside the parentheses, we can also rewrite another one, like this:
[tex]\begin{gathered} 10\div(-6--6\div6) \\ 10\div(-6-(-6)\div6) \\ 10\div(-6-(-1)) \\ 10\div(-6+1) \\ 10\div(-5) \\ -2 \end{gathered}[/tex]
Notice that minus outside the parentheses work like a product (-1) x
2) Thus the answer is -2
