Solution:
Given:
[tex]f(x)=2(x-3)^2+1[/tex]
The equation of a parabola in vertex form is given by:
[tex]y=a(x-h)^2+k[/tex]
The coordinates of the vertex is given by (h,k).
Hence, comparing both equations,
[tex]\begin{gathered} f(x)=2(x-3)^2+1 \\ y=a(x-h)^2+k \\ a=2 \\ h=3 \\ k=1 \end{gathered}[/tex]
Therefore, the coordinates of the vertex is;
[tex](h,k)=(3,1)[/tex]
