Answer:
Option D is correct.
[tex]|w|=\sqrt{29}[/tex]
Explanations:
Given the dot product expression as shown:
[tex]w\cdot w=29[/tex]
Determine the value of 'w"
[tex]w^2=29[/tex]
Take the square root of both sides to have:
[tex]\begin{gathered} \sqrt{w^2}=\pm\sqrt{29} \\ w=\pm\sqrt{29} \end{gathered}[/tex]
Since we only need the magnitude of "w" and the magnitude is the positive value of the variable, hence;
[tex]|w|=\sqrt{29}[/tex]
This gives the modulus of "w"
