10c - 6(2c - 1) = -2( c- 3)
[tex]10c-6\left(2c-1\right)=-2\left(c-3\right)[/tex]in this case, we have a equation with an unknown value (c9
Step 1
operate to eliminate ()
[tex]\begin{gathered} 10c-(6\cdot2c)-(6)(-1)=-2c+6 \\ 10c-12c+6=-2c+6 \\ 10c-12c+2c=6-6 \\ 12c-12c=0 \\ 0=0 \end{gathered}[/tex]it means, that for any value of x, it will work
this equation has infinite solutions
