Given
Probability distribution table
Find
Mean and standard deviation
Explanation
mean for probability distribution is given by
[tex]mean=\sum_^xP(x)[/tex]
so , mean
[tex]\begin{gathered} 0+0.25+0.54+0.36+0.64 \\ 1.79 \end{gathered}[/tex]
standaed deviation
[tex]\begin{gathered} \sum_^x^2P(x) \\ 0+0.25+1.08+1.08+2.56 \\ 4.97 \end{gathered}[/tex]
Final Answer
mean = 1.79
standard deviation = 4.97
