The image shows the square root of 41
The root of 41 in decimal is 6.403.
As such the integers before and after 6.403 are 6 and 7
Another way to solve this is to consider the perfect square before 41 which is 36.
The square root of 36 is 6. Since 41 is higher than 36, the number before root 41 would be 6 and the next number after 6 is 7.
Hence the two numbers before and after √41 are 6 and 7
