We know that
• The angle of direction is 39.4.
,• The magnitude of the vector is 47.3 m.
To find the horizontal component, use the following formula.
[tex]v_x=v\cdot\cos \theta[/tex]Use the given information to find the horizontal component.
[tex]v_x=47.3m\cdot\cos 39.4\approx36.6m[/tex]