Answer:
2.19 x 10⁸ m/s
Explanation:
The index of refraction n and the speed of light in ethanol v are related by the following equation
[tex]n=\frac{c}{v}[/tex]Where c is the speed of light in a vacuum. Replacing n = 1.37 and c = 3 x 10⁸ m/s, we get:
[tex]\begin{gathered} v=\frac{c}{n} \\ \\ v=\frac{3\times10^8\text{ m/s}}{1.37} \\ \\ v=2.19\times10^8\text{ m/s} \end{gathered}[/tex]Therefore, the speed of light in ethanol is 2.19 x 10⁸ m/s
