Answer:
Step-by-step explanation:
equation is given as
[tex]fx=4x^{2} +5[/tex] if [tex]fx[/tex] is [tex]f(-2)[/tex] then we knew the vale of x which is [tex]-2\\[/tex] so we will substitute it in the equation as:
[tex]f(-2) = 4(-2)^{2} +5[/tex]
solve:
[tex]-2f=4(4)+5\\-2f=16+5\\-2f=21\\\frac{-2f}{-2} =\frac{21}{-2}[/tex]
[tex]f=\frac{21}{-2}[/tex]
[tex]f=-10.5[/tex]
