Answer:
5 units
Step-by-step explanation:
The distance from a point (m, n ) to the line Ax + By + C = 0 is given by
d = [tex]\frac{|Am+Bn+C|}{\sqrt{A^2+B^2} }[/tex]
For the point (- 1, 3 ) , with m = - 1 and n = 3
3x - 4y = 10 ( subtract 10 from both sides )
3x - 4y - 10 = 0
with A = 3 , B = - 4 , C = - 10
d = [tex]\frac{|3(-1)+(-4)3-10|}{\sqrt{3^2+(-4)^2} }[/tex]
= [tex]\frac{|-3-12-10|}{9+16}[/tex]
= [tex]\frac{|-25|}{\sqrt{25} }[/tex]
= [tex]\frac{25}{5}[/tex]
= 5
