Respuesta :

loneguy

[tex]\\\text{Given that, radius, r =x+3}\\\\\text{Area of circle} = 25 \pi\\\\\implies \pi r^2 = 25 \pi\\\\\implies r^2 = 25\\\\\implies r = \sqrt{25} =5\\\\\implies x+3 = 5\\\\\implies x = 5-3 =2[/tex]