9514 1404 393
Answer:
see attached
Step-by-step explanation:
a) The first 5 partial sums are listed in the table in the attachment.
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b) Sigma notation makes use of the general term shown:
[tex]\displaystyle\sum_{n=1}^\infty{\frac{3^n+(-2)^n}{6^n}}[/tex]
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c) The sum appears to be close to 3/4. (For large n, a calculator cannot evaluate the terms of the series--they are too small.) The attachment shows the 100th sum to be rounded to 3/4 (from 12 significant digits).
