Answer:
x = 8[tex]\sqrt{2}[/tex]
Step-by-step explanation:
The triangle is isosceles with legs congruent, both x
Using Pythagoras identity in the right triangle
x² + x² = 16²
2x² = 256 ( divide both sides by 2 )
x² = 128 ( take the square root of both sides )
x = [tex]\sqrt{128}[/tex] = [tex]\sqrt{64(2)}[/tex] = [tex]\sqrt{64}[/tex] × [tex]\sqrt{2}[/tex] = 8[tex]\sqrt{2}[/tex]
