Answer:
53
Step-by-step explanation:
[tex]area \: of \: the \: semicircle \\ = \frac{1}{2} \times \pi \: d \\ = \frac{1}{2} \times \frac{22}{7} \times 7 \\ = 11 {cm}^{2} \\ [/tex]
[tex]area \: of \: the \: parallelogram \\ = b \times h \\ = 7 \times 6 \\ = 42 {cm}^{2} \\ [/tex]
[tex]area \: of \: the \: whole \: figure \\ = 11 {cm}^{2} + 42 {cm}^{2} \\ = 53 {cm}^{2} \\ [/tex]
