At what input value will the function f(x)=x-5+2 begin to have real outputs?
[tex]f(x)= \sqrt{x-5+2} [/tex]

I believe the answer is 3. Based on what we know about square roots, the expression under the square root symbol must be at least zero for the output to be real.

So you have

[tex]x-5+2\geq 0[/tex]

Solving this gives you

[tex]x-3\geq 0\\x\geq 3[/tex]

Therefore, the function will begin to have real output at the input value of 3.

Hope this helped.

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elsiemarielewis elsiemarielewis · Answer 2 · 2021-12-20T20:24:38+01:00

elsiemarielewis elsiemarielewis

20-12-2021

Answer:

5

Step-by-step explanation:

x-5+2

5-5+2=0+2=2 that's a real answer so the answer is 5 :)

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At what input value will the function f(x)=x-5+2 begin to have real outputs?[tex]f(x)= \sqrt{x-5+2} [/tex]​

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At what input value will the function f(x)=x-5+2 begin to have real outputs?
[tex]f(x)= \sqrt{x-5+2} [/tex]