Answer:
[tex] \sin( \alpha ) = \frac{4}{5} [/tex]
Step-by-step explanation:
as if we form an imaginary triangle with this line as hypotenuse
we get
- base = 3 units
- perpendicular = 4 units
using Pythagoras theorem:-
hyponteuse ² = perpendicular ² + base²
hyp² = 4² + 3²
hyp² = 16 + 9
[tex]hyp = \sqrt{25} [/tex]
hyp = 5 units
[tex] \sin( \theta ) = \frac{perpendicular}{hypotenuse} \\ \sin( \theta) = \frac{4}{5} [/tex]
