Answer:
∠ A ≈ 75.7°
Step-by-step explanation:
Given
[tex]\frac{sinA}{8}[/tex] = [tex]\frac{sin58}{7}[/tex] ( cross- multiply )
7 × sinA = 8 × sin58° ( divide both sides by 7 )
sinA = [tex]\frac{8sin58}{7}[/tex] , then
∠ A = [tex]sin^{-1}[/tex] ([tex]\frac{8sin58}{7}[/tex] ) ≈ 75.7° ( to the nearest tenth )
