Answer:
1.875
Step-by-step explanation:
The rate of change is the derivative of the function.
[tex]f(x) = \frac{10}{x-4}\\\\f'(x)=10\times \frac {d}{dx}\frac{1}{x-4}\\\\f'(x)=\frac{-10}{(x-4)^{2}}\\\\f'(2) = \frac{-10}{(2-4)^{2}} =-2.5\\\\f'(8)= \frac{-10}{(8-4)^{2}} =-0.625\\[/tex]
So, the rate of change is
f'(8) - f'(2) = - 0.625 + 2.5 = 1.875
