Respuesta :

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Answer:

0.29 J/g.°C

Explanation:

Step 1: Given data

  • Added heat (Q): 49 J
  • Mass of the substance (m): 25.0 g
  • Initial temperature: 92.6 °C
  • Final temperature: 99.4 °C

Step 2: Calculate the temperature change (ΔT)

ΔT = 99.4 °C - 92.6 °C = 6.8 °C

Step 3: Calculate the specific heat of the substance (c)

We will use the following expression.

Q = c × m × ΔT

c = Q / m × ΔT

c = 49 J / 25.0 g × 6.8 °C = 0.29 J/g.°C