Respuesta :

Answer:

false

Step-by-step explanation:

  • If -1 us a solution then putting -1 in place of x will be 0

[tex] \rm \dashrightarrow \: {x}^{2} - 6x + 5 = 0 \\ \rm \dashrightarrow \: {( - 1)}^{2} - 6( - 1) + 5 = 0 \\ \rm \dashrightarrow \: 1 + 6 + 5 = 0 \\ \rm \dashrightarrow \: 7 + 5 = 0 \\ \rm \dashrightarrow \: 12 \cancel{ = }0[/tex]

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