Answer:
2x = 80. On dividing both sides by 2, we obtain. x = 40. x + 15 = 40 + 15 = 55. Hence ... Let the three consecutive multiples of 8 be 8x, 8(x + 1), 8(x + 2). Sum of ... Number after interchanging = 10 × 3x + x = 30x + x = 31x.
Answer:
33, 34, 35
Step-by-step explanation:
Semiprimes are the product of 2 prime numbers, then
11 × 3 = 33
17 × 2 = 34
7 × 5 = 35
