isabellewatters isabellewatters

03-04-2021
Chemistry

contestada

A reaction in the laboratory yields 5.98 g KAI(SO2)2, How many moles of potassium aluminum
sulfate were produced?

Respuesta :

maacastrobr maacastrobr

08-04-2021

Answer:

0.0308 mol

Explanation:

In order to convert from grams of any given substance to moles, we need to use its molar mass:

Molar mass of KAI(SO₂)₂ = MM of K + MM of Al + (MM of S + 2*MM of O)*2

Molar mass of KAI(SO₂)₂ = 194 g/mol

Now we calculate the number of moles of KAI(SO₂)₂ contained in 5.98 g:

5.98 g ÷ 194 g/mol = 0.0308 mol

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