Answer:
[tex]AC= 32[/tex]
Explanation:
Given
[tex]AB = 29[/tex]
[tex]\angle A = 25[/tex]
Required
Find AC
I will answer the question with the attached triangle
From the attachment:
[tex]\cos A = \frac{AB}{AC}[/tex]
Make AC the subject
[tex]AC= \frac{AB}{\cos A }[/tex]
This gives:
[tex]AC= \frac{29}{\cos (25)}[/tex]
[tex]AC= \frac{29}{0.9063}[/tex]
[tex]AC= 32[/tex]
