Answer:
The zeros in ascending order are 2, 7, 8.
Step-by-step explanation:
Since f(-8) = 0, it means that (x + 8) is a factor of the function f(x)= x³ - x² - 58x + 112.
I have attached the long division of this to get the remaining factors of the polynomial function.
The remaining factor is;
x² - 9x + 14
Using quadratic formula via a calculator, we have; x = 7 and x = 2
Thus,the zeros of the polynomial function f(x)= x³ - x² - 58x + 112 in ascending order are;
2, 7, 8
