To find the slope the equation is [tex]\frac{y_{2-y_{1} } }{x_{2} -x_{1} }[/tex] so for (6,2) and (3,0) the equation would look like this [tex]\frac{0-2}{3-6}[/tex] which simplies down to [tex]\frac{-2}{-3}[/tex] and a negative divided by a negative is a positive so you're slope is [tex]\frac{2}{3}[/tex] and it matches the question.
