Given:
Volume of a square base pyramid = 48 cubic inches.
Area of base = 36 sq. inches.
To find:
The height of the pyramid.
Solution:
Volume of a pyramid is
[tex]V=\dfrac{1}{3}Bh[/tex]
Where, B is the base area and h is the height of the pyramid.
Putting V=48 and B=36, we get
[tex]48=\dfrac{1}{3}(36)h[/tex]
[tex]48=12h[/tex]
[tex]\dfrac{48}{12}=h[/tex]
[tex]4=h[/tex]
Therefore, the height of the pyramid is 4 inches.
