Answer:
C₃H₂Cl
Explanation:
From the question given above, the following data were obtained:
Mole of carbon (C) = 0.9887 mole
Mole of Hydrogen (H) = 0.6591 mole
Mole of Chlorine (Cl) = 0.3295 mole
Empirical formula =?
The empirical formula for the compound can be obtained as follow:
C = 0.9887 mole
H = 0.6591 mole
Cl = 0.3295 mole
Divide by the smallest
C = 0.9887 / 0.3295 = 3
H = 0.6591 / 0.3295 = 2
Cl = 0.3295 / 0.3295 = 1
Thus, the empirical formula for the compound is => C₃H₂Cl
