jsnowman2552 jsnowman2552
  • 01-02-2021
  • Mathematics
contestada

The difference of three times Faye's age and four times Joshua's age is 31. If Faye's age is five more than twice Joshua's age, how old is Faye?

Respuesta :

paloma4343 paloma4343
  • 01-02-2021
She is 31

F-Faye
J-Joshua

F3-J4=31
F=J2+5
(J2+5)(3)-J4=31
J2+5=31
J2+5-5=31-5
J2=26
J2/2=26/2
J=13

F=13(2)+5
F=26+5
F=31
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