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  • 01-07-2020
  • Mathematics
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Simplify [tex]\frac{1}{2e} R + \frac{1}{2e} R[/tex]

Respuesta :

espinozajulia0pd4f9b espinozajulia0pd4f9b
  • 07-07-2020

Answer:

[tex]\frac{Rx + eR}{2ex}[/tex]

Step-by-step explanation:

You first calculate the product which is [tex]\frac{R}{2e}[/tex] +[tex]\frac{1}{2x} R[/tex] to [tex]\frac{R}{2e} + \frac{R}{2x}[/tex]

Then write all numerators above the least common denominator ([tex]2ex[/tex])

Now you have your answer.

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