Inrt9404 Inrt9404
  • 03-06-2020
  • Mathematics
contestada

When a number is increased by 28%, the result is 47. What is the original number to the nearest tenth?

Respuesta :

joaobezerra joaobezerra
  • 05-06-2020

Answer:

The original number was 36.7.

Step-by-step explanation:

Multipliers:

The multiplier for a increase of a% is 1 + a/100.

The multiplier for a decrease of b% is 1 - b/100.

In this question:

The original value is x.

Increased by 28%, so we have that 1 + (28/100) = 1.28x. Equals 47. We have to find x.

1.28x = 47

x = 47/1.28

x = 36.7

The original number was 36.7.

Answer Link

Otras preguntas

In Tanzania, ____ wanted to build a classless society.
what is the sum of 25 and 14?
what is the solution to this system of linear equations? 7x – 2y = –6 8x y = 3 (–6, 3) (0, 3) (1, –5) (15, –1)
how do you solve 4(x-3?
y = 4x – 10 y = 2 what is the solution to the system of equations? (3, 2) (2, 3) (–2, 2) (2, –2)
the yard behind cindy house is rectangular in shape and has a perimeter of 72 feet. if the length of the yard is 18 feet longer than the width of the yard, wha
which orderd pairs below satisfy the following equation y=7x
the order in which atomic orbitals are filled is based on what factor?
give me the ans and steps thanks
why is it best to have a resting heart rate below 70 beats per minute