Answer: [tex](x-5)^2+(y+1)^2=r^2[/tex]
Step-by-step explanation:
The area of a circle having radius r and center (h,k) is given by :-
[tex](x-h)^2+(y-k)^2=r^2[/tex] (i)
We have given that, Center of the Circle = T ( 5,-1)
Radius = 16 units
Substitute these values in (i) , we get
[tex](x-5)^2+(y-(-1))^2=(16)^2\\\\\Rightarrow\ (x-5)^2+(y+1)^2=256[/tex]
Hence, the equation represents a circle with centerT(5,-1) and a radius of 16 units would be [tex](x-5)^2+(y+1)^2=256[/tex].
