Answer:
Answer is given below with explanations
Step-by-step explanation:
[tex] \frac{ {w}^{3} + 64}{4 + w} = \frac{ {w}^{3} + {4}^{3} }{4 + w} \\ \: we \: know \: that \: {x}^{3} + {y}^{3} = (x + y)( {x}^{2} - xy + {y}^{2} ) \\ = \frac{(w + 4)( { {w}^{2} - 4w + 16)}^{2} }{w + 4} \\ on \: cancelling \: we \: get \\ the \: answer \: \\ w^{2} - 4w + 16[/tex]
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