The factor would be "[tex]\frac{1}{1024}[/tex]".
According to the question,
- [tex]51 \ minutes = 10 \frac{1}{2} \ lifes[/tex]
Copper's half life,
Now,
The factor would the mass of a sample of copper-66 decrease in 51 minutes would be:
→ [tex]\frac{5.10}{51} = 10[/tex]
then,
→ [tex](\frac{1}{2})^{10} = \frac{1}{1024}[/tex]
Thus the answer above is right.
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https://brainly.com/question/18248273
