Answer:
The answer to your question is 45 ml
Explanation:
Data
Molarity 1 = 5 M
volume 1 = ?
Molarity 2 = 1 M
volume 2 = 225 ml
Formula
Molarity 1 x volume 1 = Molarity 2 x volume 2
-Solve for volume 1
volume 1 = Molarity 2 x volume 2 / Molarity 1
-Substitution
volume 1 = (1 x 225) / 5
-Simplification
Volume 1 = 225/5
-Result
Volume 1 = 45 ml
-Conclusion
45 ml are needed to prepare 225 ml of HNO₃ 1.0 M
