lzamarron1316 lzamarron1316
  • 01-04-2020
  • Chemistry
contestada

The molar solubility of zns is 1.6 Ã 10-12 m in pure water. Calculate the ksp for zns.

Respuesta :

Tringa0 Tringa0
  • 02-04-2020

Answer:

The solubility product of zinc sulfide is [tex]2.56\times 10^{-24}[/tex].

Explanation:

Solubility of the zinc sulfide = [tex]S=1.6\times 10^{-12}[/tex]

[tex]ZnS\rightleftharpoons Zn^{2+}+S^{2-}[/tex]

                S        S

The expression of solubility product is given by :

[tex]K_{sp}=[Zn^{2+}]\times [S^{2-}][/tex]

[tex]K_{sp}=S\times S=S^2[/tex]

[tex]=1.6\times 10^{-12}\times 1.6\times 10^{-12}=2.56\times 10^{-24}[/tex]

The solubility product of zinc sulfide is [tex]2.56\times 10^{-24}[/tex].

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