Step-by-step explanation:
[tex]2 {x}^{2} - 5x - 12[/tex]
[tex]2 {x}^{2} - 8x + 3x - 12[/tex]
[tex]2x(x - 4) + 3(x - 4)[/tex]
[tex]2x + 3 = 0 \: \: x - 4 = 0[/tex]
[tex]x = \frac{ - 3}{2} \: \: x =4[/tex]
Answer:
[tex]2 {x}^{2} - 5x - 12 = 0 \\ 2 {x}^{2} - 8x + 3x - 12 = 0 \\ 2x(x - 4)3(x - 4) = 0 \\ \\ 2x + 3 = 0 \\ 2x = 0 - 3 \\ \frac{2x }{2} = \frac{ - 3}{2} \\ x = \frac{ - 3}{2} \\ \\ x - 4 = 0 \\ x = 0 + 4 \\ x = 4[/tex]
