Respuesta :

Ckaranja
Gradient of line 1 =-2
Gradient of a line perpendicular to this line;
m1*-2=-1
m1=[tex] \frac{1}{2} [/tex]
[tex]y=mx+c y= \frac{1}{2}x +c[/tex]
Replacing for x and y
-2=1/2*(-1)+c
c=-3/2
y=[tex] \frac{x}{y} \frac{1}{2} x- \frac{3}{2} [/tex]