Answer:
The answer is 2.011 *10^24
Explanation:
Looking for atoms in boron,
Molar mass of B = 10.81g/mol
There is 36.1g of B,.
Using avogadro constant = 6.023* 10^23
36.1g of B= 6.023 *10^23/10.81 * 36.1g
That is, 6.023*10^23 divided by 10.81 multiplied by 36.1g
From this calculation, we get
36.1g of boron = 2.011 * 10^24atoms.
