HotaroKim
HotaroKim HotaroKim
  • 02-03-2020
  • Physics
contestada

A lightbulb consumed 1100J in 30 minutes. Find Power, resistance, and calculate energy in kWh

Respuesta :

MathPhys
MathPhys MathPhys
  • 02-03-2020

Explanation:

30 minutes is 1800 seconds.

Power = energy / time

P = 1100 J / 1800 s

P = 0.611 W

Converting the energy from J to kWh:

1100 J × (1 Ws / 1 J) × (1 kW / 1000 W) × (1 h / 3600 s) = 3.06×10⁻⁴ kWh

To find resistance, you need to be given either the voltage or the current.

Answer Link

Otras preguntas

What is an object with a very high resistance classified as?
katherine spends 1,089.72 each month for rent and supplies to run her salon. If she charges $18 for a haircut how many hair cuts must kathrine do to cover her e
when did grass evolve?
When an object is charged, what type of subatomic particle is transferred between objects?
What are similarities between:The Han and Shang Dynasties?The Han and Xia Dynasties?Please help as it's due tomorrow and I don't have long to do it!
How do I Stargaze? Please help :)
Which sentence does not contain any errors? A. Fortunately, information on they're collars helped us locate the owners of the dogs.
What is 4p-13p-p=-150 More 2 step equations. I don't get this one at all
please give three reasons why a battle would happen in a certain area ? :)
If x= (a^2)/b, which situation would always double the value of x? (1) Doubling the value of a(2) Halving the value of a(3) Doubling the value of b(4) Halving t