Respuesta :

Willchemistry

Hey there!

Molar mass of ( C₉H₆O₃ ) =  162.14 g/mol

atomic mass H = 1.007 amu

Therefore :

H% =  atomic mass H / molar mass ( C₉H₆O₃ )   x 100

H % =  ( 1.007 /  162.14 ) x 100 =

H% = 0.00621 x 100 =

H% = 0.621

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